1.2x^2-0.5x-3.4=0

Solution for 1.2x^2-0.5x-3.4=0 equation:

1.2x^2-0.5x-3.4=0

a = 1.2; b = -0.5; c = -3.4;
Δ = b2-4ac
Δ = -0.52-4·1.2·(-3.4)
Δ = 16.57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.5)-\sqrt{16.57}}{2*1.2}=\frac{0.5-\sqrt{16.57}}{2.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.5)+\sqrt{16.57}}{2*1.2}=\frac{0.5+\sqrt{16.57}}{2.4}
$